Помогиите.... 2 cos4x - 2 cos2x = 4 cos^2 x -1

Question

Помогиите....
2 cos4x - 2 cos2x = 4 cos^2 x -1

Answer 1

2(2сos²2x-1)-2cos2x=4*(1+cos2x)/2 -1
4cos²2x-2-2cos2x-2-2cos2x+1=0
4cos²2x-4cos2x-3=0
cos2x=a
4a²-4a-3=0
D=16+48=64
a1=(4-8)/8=-1/2⇒cos2x=-1/2
2x=-2π/3+2πn U cos2x=2π/3+2πn
x=-π/3+πn U x=π/3+πn
a2=(4+8)/8=1,5⇒cos2x=1,5  нет решения