(3x-5)*(x+2)=(x+4)^2-28

Question

(3x-5)*(x+2)=(x+4)^2-28

Answer 1

(3x-5)*(x+2)=(x+4)²-28
3x²-5x+6x-10=x²+8x+16-28
3x²+x-10=x²+8x-12
2x²-7x+2=0
D=33
x₁=(7-√33)/4
x₂=(7+√33)/4