Cos2x-3cos^2 2x=0 помогите решить
Cos2x=t t-3t^2=0 t(1-3t)=0 t=0 1-3t=0 t=1/3 cos2x=0 x=-pi/4+pi/2k cos2x=1/3 x=+-1/2arcos(1/3)+pin