2(8+3a)+7(a-1) при а=7; ;5; 9(2b+3)+5(2-b) при b=1; 3; 7(5c+2)+3(1-c) при c=5; 0;...

Question

2(8+3a)+7(a-1) при а=7; ;5;
9(2b+3)+5(2-b) при b=1; 3;
7(5c+2)+3(1-c) при c=5; 0;
8(5+3d)+4(3-2d) при d=3; 4

Answer 1

2(8+3a)+7(a-1)=16+6a+7a-7=13a+9
13*7+9=91+9=100
13*5+9=65+9=74
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9(2b+3)+5(2-b)=18b+27+10-5b=13b+37
13*1+37=13+37=50
13*3+37=39+37=76
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7(5c+2)+3(1-c)=35c+14+3-3c=32c+17
32*5+17=160+17=177
32*0+17=17
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8(5+3d)+4(3-2d)=40+24d+12-8d=16d+52
16*3+52=48+52=100
16*4+52=64+52=116