1)AB=l=13
AO=R=5
BO=H=√(AB²-AO²)=√(169-25)=√144=12
2)AB=BC=l=3√2
AC=2√AB²=2AB=6√2
R=1/2AC=1/2*6√2=3√2
3)AB=BC⇒R=OC=ABcos30=6*√3/2=3√3
4)AB=BC=AC=l=12
BK=KC=6
OK=√(AO²-AK²)=√(100-36)=√64=8
BK=BCsin60=12*√3/2=6√3
BO=H=√(108-64=\)=√44=2√11
5)BO=H=12
AC=60,AK=30
l=AB=√(AK²+BK²)=√(900+576)=√1476=6√41
OK=√(BK²-BO²)=√(576-144)=√436=2√109
R=AO=√(AK²+OK²)=√(900+436)=√1336=2√324