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2\\\\ \frac{42}{n+1}>2\\\\ \frac{42}{n+1}-2>0\\\\ \frac{42-2n-2}{n+1}>0\\\\ \frac{40-2n}{n+1}>0\\\\ \frac{2(20-n)}{n+1}>0" alt="a_n= \frac{42}{n+1}\\a_n>2\\\\ \frac{42}{n+1}>2\\\\ \frac{42}{n+1}-2>0\\\\ \frac{42-2n-2}{n+1}>0\\\\ \frac{40-2n}{n+1}>0\\\\ \frac{2(20-n)}{n+1}>0" align="absmiddle" class="latex-formula">
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_________________(-1)________________(20)_________________
n∈(-1;20)
n∈N => n={1;2;3;...;19}
Ответ: 19 членов