X-y = 10 2x+3y=0 Решите систему уравнений методом подстановки.

$\left \{ {{x-y=10} \atop {2x+3y=0}} \right. \\ \left \{ {{x=10+y} \atop {2(10+y)+3y=0}} \right. \\ \left \{ {{x=10+y} \atop {20+2y+3y=0}} \right. \\ \left \{ {{x=10+y} \atop {20+5y=0}} \right. \\ \left \{ {{x=10+y} \atop {y=-4}} \right. \\ \left \{ {{x=10-4} \atop {y=-4}} \right. \\ \left \{ {{x=6} \atop {y=-4}} \right.$

Ответ: (6;-4)