А)5(х-3)-2(х-7)+7(2х+6)=7 б)11(у-4)+10(5-3у)-3(4-3у)=-6

Question

А)5(х-3)-2(х-7)+7(2х+6)=7
б)11(у-4)+10(5-3у)-3(4-3у)=-6

Answer 1

A) 5x-15-2x+14+14x+42=7
5x-2x+14x=7+15-14-42
17x=-34
x=-2
б) 11y-44+50-30y-12+9y=-6
11y-30y+9y=-6+44-50+12
-10y=0
y=0