Реши уравнение (y-3) *(4-y)=0
4у-у2-12-3у=0. у2+у=12. у(у+1)=12. у=12 . у=11
(y-3) * (4-y)=0 y-3=0 или 4-y=0 y=3 y=4
(y-3)*(4-y)=0 4y-y²-12+3y=0 y²-7y+12=0 D=49-48=1 y1=(7-1)/2=3 y2=(7+1)/2=4