log(3)(x²+6)0 -любое 5 x>0 х>0
3>1⇒x²+6<5x</p>
x²-5x+6<0</p>
y=x²-5x+6
x²-5x+6=0 D=25-24=1
x1=(5+1)/2=3 x2=(5-1)2=2
(x-2)(x-3)<0</p>
____+____2_____-_____3_____+____
x∈(2 3)
0,6<1⇒6x-x²<-8-x </p>
-x²+7x+8<0</p>
x²-7x-8>0
y=x²-7x-8
x²-7x-8=0
D=49+32=81 x1=(7+9)/2=8 x2=(7-9)/2=-1
(x-8)(x+1)>0
______+_______-1______--_____8_____+______
x∈(-∞ -1)∨( 8 +∞) ODЗ -x-8>0⇒x<-8 </p>
6x-x²>0⇒0
10>1⇒ x²-8≤2-9x⇒x²+9x-10≤0⇒y=x²+9x-10⇒x²+9x-10=0
D=81+40=121 x1=(-9+11)/2=1 x2=(-9-11)/2=-10
(x-1)(x+10)≤0
___+______-10___-_____1__+______
ODЗ x<-√8 Ответ [-10 -√8) </p>
2log(2)(x²+10x)≥2log(2)(x-14)
log(2)(x²+10x)≥log(2)(x-14)
2>1⇒x²+10≥x-14