Решите пожалуйста 946(в) !!!!

Решите задачу:

$1)1,5+2 \frac{2}{3} = \frac{15}{10} + \frac{8}{3} = \frac{45+80}{30} = \frac{125}{30} = \frac{25}{6} \\ 2) \frac{25}{6} +3 \frac{3}{4} = \frac{25}{6} + \frac{15}{4} = \frac{50+45}{12} = \frac{95}{12} \\ 3) \frac{95}{12} *3,6= \frac{95}{12}* \frac{36}{10} = \frac{57}{2} \\ 4)15 \frac{1}{8} :2= \frac{121}{8} * \frac{1}{2}= \frac{121}{16} =7 \frac{9}{16} \\ 5)7 \frac{9}{16} -14=-6 \frac{7}{16} \\ 6) \frac{57}{2} :(-6 \frac{7}{16} )= \frac{57}{2} *(- \frac{16}{103} )=- \frac{456}{103} =$
$=-4 \frac{44}{103}$