упрастите выражение: а) c8c^15/(c^7)^2 б) -x^3y^2+2x^3y^2-3x^3y^2 в)...

$\frac{c^1*c^{15}}{(c^7)^2}=\frac{c^{16}}{c^{14}}=c^2$

$-x^3y^2+2x^3y^2-3x^3y^2=(-1+2-3)x^3y^2=-2x^3y^2$

$\frac{(2ab^3)^4}{(2a^2b)^2}=\frac{2^4a^4b^{12}}{2^2a^4b^2}=2^2a^0b^{10}=4b^{10}$

$\frac{(n^8)^4*n^1}{(n^3)^{11}}= \frac{n^{33}}{n^{33}}=1$

$\frac{10^9}{(2^3)^3*(5^3)^2}=\frac{2^9*5^9}{2^9*5^6}=2^0*5^3=125$

$(3/4)^8*(4/3)^7 \ ; \ (-0,75)^0\\(3/4)^8*(3/4)^{-7} \ ; \ 1\\(3/4)^1 \ ; \ 1\\ 3/4<1;\\(3/4)^8*(4/3)^7<(-0,75)^0$

$\frac{(25x^3)^2*(5x^5)^3}{(125x^8)^2}=-160\\\frac{(5^2x^3)^2*(5x^5)^3}{(5^3x^8)^2}=-160\\\frac{(5^4x^6)*(5^3x^{15})}{5^6x^{16}}=-160\\5^{4+3-6}*x^{6+15-16}=-160\\5^1*x^5=-160\\x^5=-32\\x=-2$