Область визначення функції: f(x) = \sqrt{log0,4x+1

Question

Область визначення функції: f(x) = \sqrt{log0,4x+1

Answer 1

0} \atop {\log_{0.4}x+1 \geq 0}} \right. \to \left \{ {{x>0} \atop {\log_{0.4}0.4x \geq \log_{0.4}1}} \right. \to \left \{ {{x>0} \atop {0.4x \leq 1}} \right. \to \left \{ {{x>0} \atop {x \leq 2.5}} \right. " alt=" \left \{ {{x>0} \atop {\log_{0.4}x+1 \geq 0}} \right. \to \left \{ {{x>0} \atop {\log_{0.4}0.4x \geq \log_{0.4}1}} \right. \to \left \{ {{x>0} \atop {0.4x \leq 1}} \right. \to \left \{ {{x>0} \atop {x \leq 2.5}} \right. " align="absmiddle" class="latex-formula">

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Comments

спасибо большое)