Найдите область определения функции у=√(2х+3)(х-1)
у=√(2х+3)(х-1)
(2x+3)(x-1)>=0
2(x+1,5)(x-1)>=0
+ - +
__________ -1,5________________ 1 ____________________
![(-\infty; -1,5]\cup[1;+\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%3B+-1%2C5%5D%5Ccup%5B1%3B%2B%5Cinfty%29 "(-\infty; -1,5]\cup[1;+\infty)")