Помогите, пожплуйста, решить! √3 ctg(pi/3 -x)= -3
√3ctg(π/3 - x)=-3 ctg(π/3 - x) = -3/√3 π/3 - x = 2π/3 + πn, n ∈ Z -x = 2π/3 - π/3 + πn, n ∈ Z x=-π/3 - πn, n ∈ Z
√3 ctg(π/3 -x)= -3 - ctg(x- πi/3 )= -3 / √3 x -π/3 = arcrg(√3) + πn, n∈Z x -π/3 = π/6 + πn, n∈Z x = π/3+ π/6 + πn, n∈Z x = π/2 + πn, n∈Z