а)4sin^2(3x)<3 б)sin(2x)*cos(2x)<0,25

Question

а)4sin^2(3x)<3</p>

б)sin(2x)*cos(2x)<0,25</p>

Answer 1

sin4x<1/8</p>

П-arcsin1/8+2Пk<4x<2П+arcsin1/8+2Пk</p>

П(2k+1)/4-1/4arcsin1/8

sin^23x<3/4</p>

sinx

 

2/3П+2Пk

 

sinx>-sqrt(3)/2

2/3П+2Пk

U

5П/3+2Пk