0
\\\
-\sin x+\frac{1}{2} >0
\\\
-\sin x>-\frac{1}{2}
\\\
\sin x<\frac{1}{2}
\\\
x\in(- \frac{7 \pi }{6} +2 \pi n; \ \frac{ \pi }{6} +2 \pi n), \ n\in Z" alt="f(x)=\cos x+\frac{x}{2}
\\\
f'(x)=-\sin x+\frac{1}{2}
\\\
f'(x)>0
\\\
-\sin x+\frac{1}{2} >0
\\\
-\sin x>-\frac{1}{2}
\\\
\sin x<\frac{1}{2}
\\\
x\in(- \frac{7 \pi }{6} +2 \pi n; \ \frac{ \pi }{6} +2 \pi n), \ n\in Z" align="absmiddle" class="latex-formula">