A) 3(x-1)>2(3-x) в) 5(x-1)+7_<1-3(x+2) б) -2-3x+1_<4

Question

A) 3(x-1)>2(3-x) в) 5(x-1)+7_<1-3(x+2) б) -2-3x+1_<4<br>

Answer 1

3(x-1)>2(3-x)3х-3>6-2x
3x+2x>6+3
5x>9
x>9/5
x>1.8 в) 5(x-1)+7_<1-3(x+2)</span>5x-5+7_<1-3x-6</span>5x+2_<-3x-5<br>5x+3x_<-5-2<br>8x_<-7<br>x_<-7/8<br> б) -2-3x+1_<4</span>
-1-3x_<4<br>-3x_<4+5<br>-3x_<9<br>x_<9/(-3)<br>x_<-3</span>