ООФ:
x^2+4x-12>0;\\D=64; \\x_1= \frac{-4+8}{2}=2;
\\x_2= \frac{-4-8}{2}=-6;\\ (x-2)(x+6)>0;
\\ ++++(-6)-------2++++\\ x \in (- \infty;-6) \cup (2; +\infty)." alt="y= \frac{3}{\sqrt{x^2+4x-12}};\\\sqrt{x^2+4x-12} \neq 0\\
=> x^2+4x-12>0;\\D=64; \\x_1= \frac{-4+8}{2}=2;
\\x_2= \frac{-4-8}{2}=-6;\\ (x-2)(x+6)>0;
\\ ++++(-6)-------2++++\\ x \in (- \infty;-6) \cup (2; +\infty)." align="absmiddle" class="latex-formula">