Укажите промежуток, которому принадлежит множество решений неравенства -2<=(4x-2)/7<=5 <br> 1)(6; 10) 2)(5; 11) 3)(6;11] 4)[6; 10]
Решите задачу:
![-2\leq\frac{4x-2}{7}\leq5;\\
-2\cdot7\leq\frac{4x-2}7\cdot7\leq5\cdot7;\\
-14\leq4x-2\leq35;\\
-14+2\leq4x-2+2\leq35+2;\\
-12\leq4x\leq37;\\
\frac{-12}{4}\leq\frac{4x}{4}\leq\frac{37}{4};\\
-3\leq x\leq 9\frac14;\\
x\in[-3; \ 9\frac14]](https://tex.z-dn.net/?f=-2%5Cleq%5Cfrac%7B4x-2%7D%7B7%7D%5Cleq5%3B%5C%5C%0A-2%5Ccdot7%5Cleq%5Cfrac%7B4x-2%7D7%5Ccdot7%5Cleq5%5Ccdot7%3B%5C%5C%0A-14%5Cleq4x-2%5Cleq35%3B%5C%5C%0A-14%2B2%5Cleq4x-2%2B2%5Cleq35%2B2%3B%5C%5C%0A-12%5Cleq4x%5Cleq37%3B%5C%5C%0A%5Cfrac%7B-12%7D%7B4%7D%5Cleq%5Cfrac%7B4x%7D%7B4%7D%5Cleq%5Cfrac%7B37%7D%7B4%7D%3B%5C%5C%0A-3%5Cleq+x%5Cleq+9%5Cfrac14%3B%5C%5C%0Ax%5Cin%5B-3%3B+%5C+9%5Cfrac14%5D "-2\leq\frac{4x-2}{7}\leq5;\\
-2\cdot7\leq\frac{4x-2}7\cdot7\leq5\cdot7;\\
-14\leq4x-2\leq35;\\
-14+2\leq4x-2+2\leq35+2;\\
-12\leq4x\leq37;\\
\frac{-12}{4}\leq\frac{4x}{4}\leq\frac{37}{4};\\
-3\leq x\leq 9\frac14;\\
x\in[-3; \ 9\frac14]")