(x+10)(x-5)-(x-6)(x+3)=16 (3x+7)(8x+1)=(6x-7)(4x-1)+93x

Question

(x+10)(x-5)-(x-6)(x+3)=16
(3x+7)(8x+1)=(6x-7)(4x-1)+93x

Answer 1

1)x^2-5x+10x-50-x^2+3x-6x-18=16
x^2+5x-50-x^2-3x-18=16
2x-68=16
2x=16+68
2x=84
x=42