Как решить 48 целых 3/4-14 целых 4/6

$48 \frac{3}{4} -14 \frac{4}{6} =48-14+ \frac{9-8}{12} =34 \frac{1}{12}$
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$48 \frac{3}{4} -14 \frac{4}{6} =48 \frac{9}{12}-14 \frac{8}{12} =34 \frac{1}{12}$

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$31 \frac{11}{18} -8 \frac{3}{4} -11 \frac{15}{36} +2 \frac{7}{9} =(31-8-11+2)+( \frac{22-27-15+28}{36} )=14 \frac{8}{36} =$ $=14 \frac{2}{9}$

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$31 \frac{11}{18} -8 \frac{3}{4} -11 \frac{15}{36} +2 \frac{7}{9} =14 \frac{2}{9} \\ \\ 1)31 \frac{11}{18} -8 \frac{3}{4} =31 \frac{22}{36}-8 \frac{27}{36} =22 \frac{31}{36} \\ 2)22 \frac{31}{36} -11 \frac{15}{36} =11 \frac{16}{36} =11 \frac{4}{9} \\ 3)11 \frac{4}{9} +2 \frac{7}{9} =13 \frac{11}{9} =14 \frac{2}{9}$
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$36 \frac{3}{4} -(12 \frac{5}{6} -8 \frac{1}{2} )+9 \frac{2}{3} =42 \frac{1}{12} \\ 1)12 \frac{5}{6} -8 \frac{1}{2} =12 \frac{5}{6} -8 \frac{3}{6} =4 \frac{2}{6} =4 \frac{1}{3} \\ 2)36 \frac{3}{4} -4 \frac{1}{3} =36 \frac{9}{12} -4 \frac{4}{12} =32 \frac{5}{12} \\ 3)32 \frac{5}{12} +9 \frac{2}{3} =32 \frac{5}{12} +9 \frac{8}{12} =41 \frac{13}{12} =42 \frac{1}{12}$