Решить систему уравнений: {x^3+y^3=9 {x*y=2

$\left \{ {1){y=2/x} \atop 2){x^{3}+8/x^{3}=9 }} \right.$
2) $x^{6} +8=9 x^{3}$
Пусть

x^{6}= a^{2} => a^{2}+8=9a => a^{2}-9a+8=0 =>" alt=" x^{3} =a => x^{6}= a^{2} => a^{2}+8=9a => a^{2}-9a+8=0 =>" align="absmiddle" class="latex-formula">

x^{3} _{1}=8=> x _{1}=2; x^{3} _{2}=1 => x _{2}=1" alt=" a_{1} =8; a_{2} =1 => x^{3} _{1}=8=> x _{1}=2; x^{3} _{2}=1 => x _{2}=1" align="absmiddle" class="latex-formula">
$y_{1}=2/2=1; y_{2}=2/1=2$
Ответ: (2;1), (1;2)