Помогите решить выражение cos(pi/6 - 2x)= -1
Cos(π/6 - 2x) = - 1 cos(2x - π/6) = - 1 2x - π/6 = π + 2πk, k∈Z 2x = π/6 + π + 2πk, k∈Z 2x = 7π/6 + 2πk, k∈Z x = 7π/12 + πk, k∈Z