I. Степенная функция. 10 класс.(задание ** фото)

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I. Степенная функция. 10 класс.(задание на фото)


image

Алгебра (221 баллов) | 20 просмотров
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\sqrt{x+1}<x-1image0}} \right. " alt=" \left \{ {{x+1<(x-1)^2} \atop {x+1 \geq 0}} \atop {x-1>0}} \right. " align="absmiddle" class="latex-formula"> ⇔ image1}} \right. " alt=" \left \{ {{x+11}} \right. " align="absmiddle" class="latex-formula"> ⇔ image0} \atop {x \geq-1}} \atop {x>1}} \right. " alt=" \left \{ {{x^2-2x+1-x-1>0} \atop {x \geq-1}} \atop {x>1}} \right. " align="absmiddle" class="latex-formula"> ⇔ image0} \atop {x \geq-1}} \atop {x>1}} \right. " alt=" \left \{ {{x^2-3x>0} \atop {x \geq-1}} \atop {x>1}} \right. " align="absmiddle" class="latex-formula"> ⇔ image0} \atop {x \geq-1}} \atop {x>1}} \right. " alt=" \left \{ {{x(x-3)>0} \atop {x \geq-1}} \atop {x>1}} \right. " align="absmiddle" class="latex-formula">
_____________0\\\\\\\\\\\\\\\\\\\\\_3_\\\\\\\\\\\\\\\\\_x
___________________1/////////////////////////////////_x
______-1\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\_x
Ответ: x∈(3;+бесконечность)




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