Решите неравенство log(x+3)по основанию 1/2 >-2
- -2 \\ log_{2} (x+3) < 2 \\ log_{2}(x+3) < log_{2} 4 \\ x+3 < 4 \\ x < 1" alt="- log_{2} (x+3) > -2 \\ log_{2} (x+3) < 2 \\ log_{2}(x+3) < log_{2} 4 \\ x+3 < 4 \\ x < 1" align="absmiddle" class="latex-formula">