Упростите выражение!!!
(3x/9-x^2 + 1/x-3) / x/x^2-6x+9=(3x/(3-x)(3+x) + 1/x-3) / x/x-3= (3x+3+x/(3-x)(3+x)) / x/x-3=4x+3/(3-x)(3+x) * x-3/x=4x+3/3+x x^2-6x+9=0 D=36-36=0 x=3
1) (3/(9-х^2)+1/(х-3)=3/(3-х)(3+х) + 1/(х-3)= -(3/(х-3)(х+3)) + 1/(х-3)= 3/(3-х)(3+х) - 3-х/(3-х)(3+х)= 3-3-х/(9-х)^2= -х/(9-х)^2 2) -х/(9-х)^2 ÷ х/х^2-6х+9= -х/(9-х)^2 × х^2-6х+9/х= х/(х-3)(х+3) × (х-3)^2/х= х-3/х+3 ответ: х-3/х+3