SUM = (1/(a²-5ab)-1/(a²+5ab))(25b²-a²)/(5b²)= (((a²+5ab)-(a²-5ab))/((a²-5ab)(a²+5ab)))(25b²-a²)/(5b²)= (((10ab))/(a²(a-5b)(a+5b)))(25b²-a²)/(5b²)= (((10ab))/(a²(a²-25b²)))(25b²-a²)/(5b²)= -(10ab)/(5a²b²)=-2/(ab) a=1, b=2 SUM = -2/(1·2)= -1