Sin(2π+t)+cos(3π/2+t)=1

Question

Sin(2π+t)+cos(3π/2+t)=1

Answer 1

Cos(2π-t)-sin(3π/2+t)=1 
cost+cost=1 
cost=1/2 
t=±π/3+2πn

Answer 2

Sin(2π+t) +cos(3π/2 +t) = 1
используя формулы приведения, получаем
sin t + sin t = 1
2 sin t = 1
   sin t = 1/2
    t = (-1)∧k arcsin 1/2 + πk, k∈Z
    t = (-1)∧k × π/6 + πk, k∈Z