Sin2x+4cos^2x=0 решить уравнение
Sin2x + 4cos^2x = 0 2sinxcosx + 4cos^2x = 0 cosx(2sinx + 4cosx) = 0 1) cosx = 0 x1 = π/2 + πn, n∈Z 2) 2sinx + 4cosx = 0 /(2cosx ≠ 0) tgx+ 2 = 0 tgx = - 2 x2 = arctg(- 2) + πk, k∈Z x2 = - arctg(2) + πk, k∈Z