(3cos(-2п - B) + 3sin(п/2 +В))/5cos(B+3п)

Question

(3cos(-2п - B) + 3sin(п/2 +В))/5cos(B+3п)

Answer 1

= (3* cos (-b) + 3* cos b) / 5 *(-cos b) = (3 cos b + 3 cos b) / - 5 cos b = 
= 6 cos b / - 5 cos b = - 6/5 = -1,2