0\\\\log_3x+\frac{1}{2}log_3x+\frac{1}{3}log_3x=\frac{11}{12}\\\\\frac{11}{6}log_3x=\frac{1}{12}\\\\log_3x=\frac{1}{2}\\\\x=3^{\frac{1}{2}}=\sqrt3" alt="log_3x+log_{3^2}x+log_{3^3}x=\frac{11}{12}\; ,\; \; ODZ:\; x>0\\\\log_3x+\frac{1}{2}log_3x+\frac{1}{3}log_3x=\frac{11}{12}\\\\\frac{11}{6}log_3x=\frac{1}{12}\\\\log_3x=\frac{1}{2}\\\\x=3^{\frac{1}{2}}=\sqrt3" align="absmiddle" class="latex-formula">