Найдите значение выражения(92/5*1,5+0,4)*1/7-(1/6+3,5)/ дробь

Решите задачу:

$( \frac{92}{5} *1,5+0,4)* \frac{1}{7} -( \frac{1}{6} +3,5)= ( \frac{92}{5}* \frac{15}{10} +0.4)* \frac{1}{7} -( \frac{1}{6}+ \frac{35}{10} )= \\ = ( \frac{276}{10} + \frac{4}{10} )* \frac{1}{7} -( \frac{5}{30}+ \frac{105}{30} )= ( \frac{280}{10} )* \frac{1}{7} -( \frac{110}{30} )= \\ = \frac{40}{10} - \frac{110}{30} = \frac{120-110}{30} = \frac{10}{30} = \frac{1}{3}$