Решите,нужен только ответ {4х-12 больше либо равно 0 {х-6<1

$\left \{ {{4x-12 \geq 0} \atop {x-6<1} \right. \Rightarrow \left \{ {{4x \geq 12} \atop {x<1+6} \right. \Rightarrow\Rightarrow \left \{ {{x \geq 3} \atop {x<7} \right. \Rightarrow$
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--------------------[3]----------------------(7)-----------------------
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Ответ. [3;7)