Номер 4 срочно❗️))))))))))))

Решите задачу:

$x^ \alpha \cdot x^ \beta =x^{ \alpha + \beta } \\\ \frac{x^ \alpha }{x^ \beta } =x^{ \alpha - \beta } \\\ (x^ \alpha )^ \beta =x^{ \alpha \beta }$

$a^{0.6}\cdota^{3.4}=a^{0.6+3.4}=a^4 \\\ a^{- \frac{3}{7} }a^{ \frac{5}{14} }=a^{- \frac{3}{7}+\frac{5}{14} }=a^{- \frac{6}{14}+\frac{5}{14} }=a^{- \frac{1}{14}} \\\ (a^ \frac{5}{17} )^{ \frac{3}{5} }=a^ {\frac{5}{17}\cdot \frac{3}{5} }=a^\frac{3}{17}$

$a^{ \frac{7}{15} }:a^\frac{1}{6} =a^{ \frac{7}{15}-\frac{1}{6}}=a^{ \frac{14}{30}-\frac{5}{30}}=a^ \frac{9}{30} =a^ \frac{3}{10}= a^{0.3} \\\ (a^{-0.8})^4\cdot(a^{-1.4})^{-2}:(a^{0.4})^{-6}= a^{-0.8\cdot4}\cdot a^{-1.4\cdot(-2)}:a^{0.4\cdot (-6)}= \\\ =a^{-3.2}\cdot a^{2.8}:a^{-2.4}=a^{-3.2+2.8-(-2.4)}=a^2 \\\ (a^\frac{5}{18}a^ \frac{10}{27})^ \frac{9}{5}=a^{(\frac{5}{18}+\frac{10}{27})\cdot\frac{9}{5} } = a^{(\frac{15}{54}+\frac{20}{54})\cdot\frac{9}{5}}=a^{\frac{35}{54}\cdot\frac{9}{5}}= a^{\frac{7}{6}$