Решите уравнение (х+10)²=(2-х)²
(х+10)²=(2-х)² х²+20х+100=4-4х+х² х²+20х+100-4+4х-х²=0 24х+96=0 24х=-96 Х= -4
(x+10)^2=(2-x)^2 x^2+20x+100-4+4x-x^2=0 20x+4x=-100+4 24x=-96 x=-4