Cos (2pi-x) - sin (3pi/2+x) = 1

Question

Cos (2pi-x) - sin (3pi/2+x) = 1

Answer 1

cos (2pi-x) - sin (3pi/2+x) = 1

cosx+cosx=1

2cosx=1

cosx=1/2

х= +-п/3 +2п n,  n e Z