(2-7х)(5+4х)=0 Решите уравнение!
2-7х=0...........=>....7х=2........=>.......х1=3,5 5+4х=0..................4х=-5..................х2=-1,25
10+8x-35x-28x^2=0 -28x^2-27x+10=0 | * (-1) 28x^2 + 27x - 10=0 Д = 729 +1120=1849 x1= -27+46/56= 19/56 x2= -27-46/56= -73/56