Элетролитическая диссоциация веществ: CaHPO4, Ba(OH)2, (CuOH)2, SO4, HF, H2SO4

Question

Элетролитическая диссоциация веществ: CaHPO4, Ba(OH)2, (CuOH)2, SO4, HF, H2SO4

Answer 1

CaHPO₄ = Ca²⁺ + HPO₄²⁻
HPO₄²⁻ = H⁺ + PO₄³⁻
Ba(OH)₂ = BaOH⁺ + OH⁻
BaOH⁺ = Ba²⁺ + OH⁻
(CuOH)₂SO₄ = 2CuOH⁺ + SO₄²⁻
CuOH⁺ = Cu²⁺ + OH⁻
HF = H⁺ + F⁻
H₂SO₄ = H⁺ + HSO₄⁻
HSO₄⁻ = H⁺ + SO₄²⁻