0\\\\\frac{(x-2)(x+2)}{2x-3}<0\\\\---(-2)+++(\frac{3}{2})---(2)+++++\\\\x\in (-\infty,-2)U(\frac{3}{2},2)" alt="\frac{(2-x)(2+x)}{2x-3}>0\\\\\frac{(x-2)(x+2)}{2x-3}<0\\\\---(-2)+++(\frac{3}{2})---(2)+++++\\\\x\in (-\infty,-2)U(\frac{3}{2},2)" align="absmiddle" class="latex-formula">