0} \atop {x>0}} \right. ,\; x>\frac{3}{4}\\\\ln(4x-3)=lnx^2\\\\4x-3=x^2\\\\x^2-4x+3=0\\\\x_1=1,\; x_2=3\; (teor.\; Vieta)" alt="ln(4x-3)=2lnx,\; OOF:\; \left \{ {{4x-3>0} \atop {x>0}} \right. ,\; x>\frac{3}{4}\\\\ln(4x-3)=lnx^2\\\\4x-3=x^2\\\\x^2-4x+3=0\\\\x_1=1,\; x_2=3\; (teor.\; Vieta)" align="absmiddle" class="latex-formula">