![image](https://tex.z-dn.net/?f=h%3D+%5Cfrac%7Bat%5E2%7D%7B2%7D%3D%3Ea%3D+%5Cfrac%7B2h%7D%7Bt%5E2%7D+%5C%5C+a_%7Bpapa%7D%3D+%5Cfrac%7B2%2A7%2C5%7D%7B8%2C6%5E2%7D+%5Capprox+0%2C2+%5C+m%2Fc%5E2+%5C%5C+%0Aa_%7Bsin%7D%3D+%5Cfrac%7B2%2A7%2C5%7D%7B7%2C1%5E2%7D+%5Capprox++0%2C3+%5C+m%2Fc%5E2+%5C%5C++%5C%5C+%0AF-mg%3Dma%3D%3EF%3Dma%2Bmg%3Dm%28g%2Ba%29+%5C%5C+F_%7Bpapa%7D%3D75%289%2C8%2B0%2C2%29%3D750+%5C+H+%5C%5C+%0AF_%7Bsin%7D%3D50%289%2C8%2B0%2C3%29%3D505%5C+H+%5C%5C++%5C%5C+%0AA%3DFh+%5C%5C+A_%7Bpapa%7D%3DF_%7Bpapa%7Dh%3D750%2A7%2C5%3D5625%5C%5C+%0AA_%7Bsin%7D%3DF_%7Bsin%7Dh%3D505%2A7%2C5%3D3787%2C5)
a= \frac{2h}{t^2} \\ a_{papa}= \frac{2*7,5}{8,6^2} \approx 0,2 \ m/c^2 \\
a_{sin}= \frac{2*7,5}{7,1^2} \approx 0,3 \ m/c^2 \\ \\
F-mg=ma=>F=ma+mg=m(g+a) \\ F_{papa}=75(9,8+0,2)=750 \ H \\
F_{sin}=50(9,8+0,3)=505\ H \\ \\
A=Fh \\ A_{papa}=F_{papa}h=750*7,5=5625\\
A_{sin}=F_{sin}h=505*7,5=3787,5" alt="h= \frac{at^2}{2}=>a= \frac{2h}{t^2} \\ a_{papa}= \frac{2*7,5}{8,6^2} \approx 0,2 \ m/c^2 \\
a_{sin}= \frac{2*7,5}{7,1^2} \approx 0,3 \ m/c^2 \\ \\
F-mg=ma=>F=ma+mg=m(g+a) \\ F_{papa}=75(9,8+0,2)=750 \ H \\
F_{sin}=50(9,8+0,3)=505\ H \\ \\
A=Fh \\ A_{papa}=F_{papa}h=750*7,5=5625\\
A_{sin}=F_{sin}h=505*7,5=3787,5" align="absmiddle" class="latex-formula">
Большую работу выполнит отец на 1837,5 Дж, что есть логичным.