3 sin 240°/ cos 390° - √3 tg420°

Question

3 sin 240°/ cos 390° - √3 tg420°

Answer 1

=3sin(270-30) / cos(360+30) -coren3 * tg(360+60)=
=-3cos30 /cos30-coren3 *tg60=-3-coren3 *coren3=-3-3=-6