(3/2x-y)-(2/2x+y)-(1/2x-5y):y²/4x²-y²помогите пожалуйста

Решите задачу:

$( \frac{3}{2x-y} - \frac{2}{2x+y} - \frac{1}{2x-5y} )* \frac{4 x^{2} - y^{2}}{ y^{2}} =$
$\frac{(6x+3y)(2x-5y)-(4x-2y)(2x-5y)-(2x-y)(2x+y)}{ y^{2} (2x-5y)} =$
$\frac{(2x-5y)(6x+3y-4x+2y)-(2x-y)(2x+y)}{ y^{2} (2x-5y)} =\frac{(2x-5y)(2x+5y)-(2x-y)(2x+y)}{ y^{2} (2x-5y)} =$
$\frac{(4 x^{2} -25 y^{2}-4 x^{2} + y^{2})}{ y^{2} (2x-5y)} = \frac{-24}{2x-5y}$