Log4(x-3)=1+log4(x-6)

Question

Log4(x-3)=1+log4(x-6)

Comments

спасибо!!!

Answer 1

Lo4(x-3)=Log4(4(x-6));
X-3=4x-24;
x-4x=-24+3;
-3x=-21;
x=-21:(-3);
x=7;
ОДЗ:х-3>0;х-6>0;
х>3;х>6;
(6;+~)
Ответ:7

Answer 2

Log(4)(x-3)-log(4)(x-6)=1
log(4)(x-3)/(x-6)=1
ОДЗ
x-3>0⇒x>3 U x-6>0⇒x>6⇒x∈(6;≈)
(x-3)/(x-6)=4
x-3=4x-24
4x-x=-3+24
3x=21
x=7