5|-х|=3; 1,5|-х|=6; 2/3|х|=4;

Решите задачу:

$5|-x|=3; \\ |-x|= \frac{3}{5} ; \\ \left [ {{-x= \frac{3}{5},} \atop {-x=- \frac{3}{5};}} \right. \left [ {{x=- \frac{3}{5},} \atop {x= \frac{3}{5};}} \right. \\ \\ 1,5|-x|=6; \\ |-x|=4; \\ \left [ {{-x= 4,} \atop {-x=-4;}} \right. \left [ {{x=- 4,} \atop {x=4;}} \right. \\ \\ \frac{2}{3}|x|=4; \\ |x|=6; \\ \left [ {{x=-6,} \atop {x=6;}} \right.$