Упростите выражение:1) х2-10х+25/3х+12/2х-10/х2-16 2) а2-25/а+3*1/а2+5а-а+5/а2-3а .

Решите задачу:

$1) = \frac{(x-5) ^{2}(x-4)(x+4) }{3(x+4)2(x-5)}= \frac{(x-5)(x-4)}{6} \\ 2) = \frac{(a-5)(a+5)}{(a+3)a(a+5)} - \frac{a+5}{a(a-3)} = \frac{a-5}{a(a+3)} - \frac{a+5}{a(a-3)} = \frac{(a-5)(a-3)-(a+5)(a+3)}{a(a-3)(a+3)} = \\ = \frac{a ^{2}-5a-3a+15-a ^{2}-5a-3a-15 }{a(a ^{2}-9) } = \frac{-16a}{a(a ^{2}-9) }= -\frac{16}{(a ^{2}-9) }$