Помогите срочно надо!!!!!!!
1) 2) = 3) y' = (1/e^(tg^2(x^4-3∛x)))*(e^(tg^2(x^4-3∛x)))*(2tg(x^4-3∛x))*(1/cos^2(x^4-3∛x))*(4x^3-x^(-2/3)) = (2tg(x^4-3∛x)*(4x^3-x^(-2/3))/(cos^2(x^4-3∛x))