0,\; \; +++(-1)---[\frac{3}{2}]+++\\\\x\in (-\infty,-1)U[\frac{3}{2},+\infty)" alt=" \frac{x-1}{x+4} \leq 0,\; +++(-4)---[1]+++\\\\x\in (-4,1] \\ \\ \\ \frac{2x-3}{x+1}>0,\; \; +++(-1)---[\frac{3}{2}]+++\\\\x\in (-\infty,-1)U[\frac{3}{2},+\infty)" align="absmiddle" class="latex-formula">