0}} \right. \\
\left \{ {{ \frac{4x+3x}{12}<7 } \atop { \frac{6-x}{6} >0}} \right. \\
\left \{ {{ \frac{4x+3x}{12}< \frac{7*12}{12} } \atop { 6-x>0}} \right. \\
\left \{ {{ 7x<7*12 } \atop { -x>-6}} \right. \\
\left \{ {{ x<12 } \atop { x<6}} \right. " alt=" \left \{ {{ \frac{x}{3}+ \frac{x}{4} <7 } \atop {1- \frac{x}{6} >0}} \right. \\
\left \{ {{ \frac{4x+3x}{12}<7 } \atop { \frac{6-x}{6} >0}} \right. \\
\left \{ {{ \frac{4x+3x}{12}< \frac{7*12}{12} } \atop { 6-x>0}} \right. \\
\left \{ {{ 7x<7*12 } \atop { -x>-6}} \right. \\
\left \{ {{ x<12 } \atop { x<6}} \right. " align="absmiddle" class="latex-formula">
x<6<br>Ответ: х∈(-∞;6)